java - Given a number n and two integers p1,p2 determine if the bits in position p1 and p2 are the same or not. Positions p1,p2 and 1 based -

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i've been doing little code quizes catch on coding after graduating 1 got stump. here's question:

given number n , 2 integers p1,p2 determine if bits in position p1 , p2 same or not. positions p1,p2 , 1 based.

example

22,3,2 true because it's 0001 0110 because 2 , 3 position same.

i solved 1 way convert decimal binary , string , check if bits in positions same, feel there's easier way bit manipulation i'm not it. thinking if shift bits first position , compare them answer ran problem when shift them shift left since overflow.

you shift interesting bits least significant position , mask off other bits &.

assuming p1 , p2 zero-based indexes counting least significant bit:

bool same_bits = (((n >> p1) & 1) == ((n >> p2) & 1))

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