java - no throws clause -

this program correct , compile , run. why method 'a' not have throws declaration?

class exception1 {       public void a()          {             int array[] = new int[5];             try             {                 system.out.println("try");                 array[10]=1;             }             catch (exception e)             {                system.out.println("exception");                  throw e;             }                         {                 system.out.println("finally");                 return;             }         }     public static void main(string[] args)          {             exception1 e1 = new exception1();              try {                 e1.a();             }              catch(arrayindexoutofboundsexception e)             {                 system.out.println("catch");             }             system.out.println("end of main");         } } 

the problem return in finally block:

since finally always executed , always complete abruptly (either unchecked exception or return), there no way throw e in catch-block (or unchecked exception in try block) ever propagated downwards on call stack.

if remove return, you'll notice compiler not accept code, stating exception not declared thrown on method a().