unix - suppress the output to screen in shell script -

hi have written small script:

#!/usr/bin/ksh  in *.dat awk 'begin{ofs=fs=","}$3~/^353/{$3="353861958962"}{print}' $i >> $i_changed awk '$3~/^353/' $i_changed >> $i_353 rm -rf $i_changed done  exit 

i tested , wrking fine. giving output screen dont need output screen. need final file made $i_353

how possible?

wrap body of script in braces , redirect /dev/null:

#!/usr/bin/ksh  { in *.dat     awk 'begin{ofs=fs=","}$3~/^353/{$3="353861958962"}{print}' $i >> $i_changed     awk '$3~/^353/' $i_changed >> $i_353     rm -rf $i_changed done } >/dev/null 2>&1 

this sends errors bit-bucket too. may not such idea; if don't want that, remove 2>&1 redirection.

also: beware - need use ${i}_changed , ${i}_353. why output not going files...your variables ${i_changed} , ${i_353} not initialized, , hence redirections don't name file.