C realloc inside a function -

here code:

#include <stdio.h> #include <stdlib.h> #include <dirent.h> #include <string.h> #include <sys/stat.h>  void mp3files(char** result, int* count, const char* path) {     struct dirent *entry;     dir *dp;      dp = opendir(path);     if (dp == null) {         printf("error, directory or file \"%s\" not found.\n", path);         return;     }      while ((entry = readdir(dp))) {         if ((result = (char**) realloc(result, sizeof (char*) * ((*count) + 1))) == null) {             printf("error");                 return;         }          result[*count] = entry->d_name;         (*count)++;     }      closedir(dp); }  int main() {      int* integer = malloc(sizeof (int));     *integer = 0;      char** mp3filesresult = malloc(sizeof (char*));         mp3files(mp3filesresult, integer, ".");      (int = 0; < *integer; i++) {         printf("ok, count: %d \n", *integer);         printf("%s\n", mp3filesresult[i]);     }      return (exit_success); } 

it gives me segmentation fault. however, when put loop:

for (int = 0; < *integer; i++) {     printf("ok, count: %d \n", *integer);     printf("%s\n", mp3filesresult[i]); } 

in end of mp3files function, works. , when change third parameter of mp3files function "." directory contains less 4 files or directories, works great. in other words, when variable mp3filesresult points @ less 4 strings, doesn't fail segmentation fault.

why keep doing ?

thanks in advance , sorry english.

you pass in char **, pointer pointer char, representing pointer "string" representing "array of string". if want reallocate array must pass reference (pass pointer it) need "pointer array of string", or char ***:

... myfunc(char ***result, ...) {     *result = realloc(*result, ...); // writing *result changes caller's pointer }   ... char **data = ...; myfunc(&data, ...);