fftw - Problem with FFTW2 routine in C -

i'm working fftw2 (fastest fourier transform in west) library, , after writing successful routine in fortran, moving on c. however, i'm having trouble data assigning when try input data transform (ie, values of sin(x)). currently, code is:

#include <stdio.h> #include <fftw.h> #include <math.h> #include <complex.h>  void compute_fft(){   int i;   const int n[8];   fftw_complex in[8];   fftwnd_plan p;    in[0]->re = 0;   in[1]->re = (sqrt(2)/2);   in[2]->re = 1;   in[3]->re = (sqrt(2)/2);   in[4]->re = 0;   in[5]->re = -(sqrt(2)/2);   in[6]->re = -1;   in[7]->re = -(sqrt(2)/2);    for(i = 0; < 8; i++){     (in[i])->im = 0;   }    p = fftwnd_create_plan(8, n, fftw_forward, fftw_esimate | fftw_in_place);   fftwnd_one(p, &in[0], null);   fftwnd_destroy_plan(p);    printf("sin\n");   for(i = 0; < 8; i++){     printf("%d\n", n[i]);   } } 

i've been using http://fftw.org/fftw2_doc/ link documentation/tutorial purposes, , error "invalid type argument of a->a (have afftw_complexa)", , 'a' characters on either side of -> , fftw_complex have carats above them. i'm using same pattern worked when wrote in fortran, , seem following tutorial, it's assignment here messing syntax on. record, compiler using nvcc, if makes difference (i tried gcc). if here has every used fftw2 in c before, correct mistake? thank you!

it might because of array "in" array of fftw_complex instead of using in[0]->re = 0 should use in[0].re = 0. unless fftw_complex again typedefined array.

fftw_complex in[8]; in[0].re = 0; in[1].re = (sqrt(2)/2); in[2].re = 1; in[3].re = (sqrt(2)/2); in[4].re = 0; in[5].re = -(sqrt(2)/2); in[6].re = -1; in[7].re = -(sqrt(2)/2);