html - How to change headers level by XSLT based on depth in XML -

my xsl-file:

        ...         <div>            <xsl:choose>             <xsl:when test="count(ancestor::node()) = 1">               <h2>             </xsl:when>             <xsl:when test="count(ancestor::node()) = 2">               <h3>             </xsl:when>           </xsl:choose>               <xsl:attribute name="id">               <xsl:value-of select="@id" />             </xsl:attribute>             <xsl:copy-of select="title/node()"/>            <xsl:choose>             <xsl:when test="count(ancestor::node()) = 1">               </h2>             </xsl:when>             <xsl:when test="count(ancestor::node()) = 2">               </h3>             </xsl:when>           </xsl:choose>           </div> 

i know not allowed split tags h2.../h2, h3.../h3 this.

but how correctly?

you recursive template , generate heading element dynamically.

for example, input xml:

<input>   <level id="1">     <title>first</title>     <level id="2">       <title>second</title>       <level id="3">         <title>third</title>       </level>     </level>   </level> </input> 

processed xslt:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform" exclude-result-prefixes="xsl"> <xsl:output omit-xml-declaration="yes" indent="yes" method="html"/> <xsl:strip-space elements="*"/>  <xsl:template match="level">   <xsl:variable name="level" select="count(ancestor-or-self::level) + 1"/>    <xsl:element name="h{$level}">     <xsl:attribute name="id">       <xsl:value-of select="@id"/>     </xsl:attribute>     <xsl:copy-of select="title/node()"/>   </xsl:element>    <xsl:apply-templates select="level"/> </xsl:template> </xsl:stylesheet> 

gives following html:

<h2 id="1">first</h2> <h3 id="2">second</h3> <h4 id="3">third</h4>