php - how to show textbox if radio button value is checked from database? -

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i have 3 radio buttons 

<input  type="radio" name="preferedpaymt" value="checkmailed" id="checkmailed1" <?php if($paymnt=="checkmail") {?> checked="checked" <?php }?> /> (a)check mailed  <input  type="radio" name="preferedpaymt" value="paypal"  <?php if($paymnt=="paypal") {?> checked="checked" <?php }?> /> (b)by paypal  <input  type="radio" name="preferedpaymt" value="wiretransfer"  id="wiretransfer" <?php if($paymnt=="wiretransfer") {?> checked="checked" <?php }?> /> (c)wire transfer bank a/c$12

but value of radiobutton checked database . these 2 tables associated if radiobutton 2 checked table1 1 should populate id tb1

here problem when value of radio button checked database table not populate if click gets populated want automatis how can it?

jquery code, using

<script type="text/javascript"> jquery(function () {     jquery("input[name=preferedpaymt]").change(function () {         if ($(this).val() == "paypal") {             jquery("#ppl").slidedown()         } else {             jquery("#ppl").slideup();         }     }); }); </script>

or culd use:

var chk_val = jquery("input[name='preferedpaymt']:checked").val(); alert(chk_val);

edit: how use it!

your inputs:

<input  type="radio" name="preferedpaymt" value="checkmailed" id="checkmailed1" <?php if($paymnt=="checkmail") {?> checked="checked" <?php }?> /> (a)check mailed  <input  type="radio" name="preferedpaymt" value="paypal"  <?php if($paymnt=="paypal") {?> checked="checked" <?php }?> /> (b)by paypal  <input  type="radio" name="preferedpaymt" value="wiretransfer"  id="wiretransfer" <?php if($paymnt=="wiretransfer") {?> checked="checked" <?php }?> /> (c)wire transfer bank a/c$12

then lets got 1 tables each payment choise. ex:

note tables has same classname because want hide of them default. id attribute set "table_paymentmethod".

<table class="payment_table" id="table_checkmailed" height="200" bgcolor="#00ff33" width="100px;" > <tr>   <td>       checked checked mail   </td> </tr> </table>  <table class="payment_table" id="table_paypal" height="200" bgcolor="#ff0000" width="100px;" > <tr>   <td>       checked paypal   </td> </tr> </table>  <table class="payment_table" id="table_wiretransfer" height="200" bgcolor="#ccc" width="100px;" > <tr>   <td>       checked wiretransfer    </td> </tr> </table>

now part jquery comes in handy.

<script type="text/javascript">  jquery(document).ready(function(){         jquery('.payment_table').hide(); // hide tables default          var chk_val = jquery("input[name='preferedpaymt']:checked").val(); // grab value of selected radio          jquery('#table_'+chk_val).slidedown(1000); // slides down right table on page load.   }); </script>

well there go, should trick you. im not best @ explaining should pretty straightforward.


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