fortran - Progress bar. [gfortran vs ifort] -

i have wrote genetic algorithm in fortran able compute long double precision generic fitness function. first version (double precision) wrote gfortran have implemented progress bar. have compile ifort because gfortran not capable of perform real*16 calculations. works fine in case (ifort) progress bar not works properly. namely when whole cycle completed progress bar printed std output.

here piece of code progress bar:

if (rate(i).gt.ratemax)  ratemax=rate(i)  write(*,"(1x,a57,d12.4,a27,f6.2,a1)",advance="no") &  '\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b ff: ', &   ratemax,'             progress:',100.*real(nmix)/real(nmixing),'%'  end if 

i use intel xeon of 64bit , options ifort are:

ifort -o2 -assume bscc ffevalld.f90  func.o -o ffevalld 

while when use gfortran compile in way:

gfortran -ffree-form -o2 -fbackslash ffeval.f func.o -o ffeval 

in gfortran (but double precision) works fine.

where mistake when use ifort? thanx

here's solution:

if (rate(i).gt.ratemax) ratemax=rate(i) 1100 format(1x,a57,d12.4,a27,f6.2,a1,$) write(*,1100) & '\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\‌​b\b\b\b\b\b\b$ ratemax,' progress:',100.*real(nmix)/real(nmixing),'%'