linux - Sh, awk: how to convert integers, visible in the shell as a string to 16-bit low-/big- endian binary integers? -

i have bash sequence,

grep "integer =" $1 | awk -f= '{printf("%d\n",int($2*327))}' 

which filters producing smth like:

6768 6572 6638 8403 8436 8436 8305 8502 

i need these numbers placed in binary file 16-bit low-endian words (or big-endian if specified). there awk-, bash- way it?

ideally, like:

grep "integer =" $1 | awk -f='{to16bit_lendian(printf("%d\n",int($2*327)))}' >> out.bin

this should work:

cat $1 | grep "integer =" | awk -f=' function out(b) {   if(b==0)   {     system("printf \"\\00\"");   }   else   {     printf("%c",b);   } } function shorttole(n) {   n%=65536;   msb=n/256;   lsb=n%256;   out(lsb);   out(msb); }  {   shorttole($2*327) } ' >> out.bin 

and optimized way removing useless cat , grep:

awk -f" =" ' function out(b) {   if(b==0)   {     system("printf \"\\00\"");   }   else   {     printf("%c",b);   } } function shorttole(n) {   n%=65536;   msb=n/256;   lsb=n%256;   out(lsb);   out(msb); }  $1 == "integer" {   shorttole($2*327) } ' $1 >> out.bin